What it frames
The Nikon Z5 IIC with the TTArtisan AF 32mm f/2.8, over a 1.75 m person in a street, with a door, a parked car and buildings. Everything is drawn to scale: the solid frame is what the camera takes in, the dashed ones are 24, 50 and 135mm on full frame from the same spot.
32mm on the Nikon Z5 IIC frames 5.62 m × 3.75 m at 5 m: like 32mm on full frame, 59° across.
The numbers
- Frame at 5 m5.62 m × 3.75 m
- Full-frame equivalent32mm
- Angle of view59° × 41°, 68° diagonal
- Depth of field at f/2.83.59 m to 8.22 m (4.63 m)
- Depth of field at f/82.36 m to infinity (to infinity)
- Hyperfocal at f/2.812.7 m
- Hyperfocal at f/84.47 m
- Circle of confusion0.029 mm
How it is worked out
The frame at a distance is distance × sensor size ÷ focal length, across and up; the angle of view is 2 × atan(sensor size ÷ (2 × focal length)). Depth of field uses the thin-lens formulas: the hyperfocal distance H = f² ÷ (N × c) + f, the near limit s(H − f) ÷ (H + s − 2f) and the far limit s(H − f) ÷ (H − s), sharp to infinity from H on, with a circle of confusion c of the sensor diagonal ÷ 1500 and, on a zoom whose aperture changes, the maximum aperture taken linearly between its ends. These are for a rectilinear lens; a fisheye takes in more. Ask for this page with Accept: application/json for the numbers alone.