What it frames

The Canon EOS 850D with the Tamron 10-24mm f/3.5-4.5 Di II VC HLD, over an 8.5 m tree and a 1.75 m person, with hills behind. Everything is drawn to scale: the solid frame is what the camera takes in, the dashed ones are 24, 50 and 135mm on full frame from the same spot. Its APS-C (Canon) sensor (22.3 x 14.9 mm) has a crop factor of 1.6, so the dashed frames are marked with the focal length that gives the same view on it.

10mm on the Canon EOS 850D frames 44.6 m × 29.8 m at 20 m: like 16mm on full frame, 96° across.

24mm eq. (15mm)50mm eq. (31mm)135mm eq. (84mm)10mm · like 16mm on full frame44.6 m × 29.8 m at 20 m
The subject is 20 m away; things behind it are drawn smaller, as the camera sees them.
Inside the frame: the picture you would get.

The numbers

  • Frame at 20 m44.6 m × 29.8 m
  • Full-frame equivalent16mm
  • Angle of view96° × 73°, 107° diagonal
  • Depth of field at f/3.51.48 m to infinity (to infinity)
  • Depth of field at f/868 cm to infinity (to infinity)
  • Hyperfocal at f/3.51.61 m
  • Hyperfocal at f/871 cm
  • Circle of confusion0.018 mm
f/3.51.48 m to infinity (everything to infinity)f/868 cm to infinity (everything to infinity)camerasubject, 20 m40 m
Depth of field: what is acceptably sharp, wide open and at f/8, focused on the subject.

How it is worked out

The frame at a distance is distance × sensor size ÷ focal length, across and up; the angle of view is 2 × atan(sensor size ÷ (2 × focal length)). Depth of field uses the thin-lens formulas: the hyperfocal distance H = f² ÷ (N × c) + f, the near limit s(H − f) ÷ (H + s − 2f) and the far limit s(H − f) ÷ (H − s), sharp to infinity from H on, with a circle of confusion c of the sensor diagonal ÷ 1500 and, on a zoom whose aperture changes, the maximum aperture taken linearly between its ends. These are for a rectilinear lens; a fisheye takes in more. Ask for this page with Accept: application/json for the numbers alone.