What it frames
The Leica TL2 with the Leica Elmarit-TL 18mm f/2.8 ASPH, over a 1.75 m person in a street, with a door, a parked car and buildings. Everything is drawn to scale: the solid frame is what the camera takes in, the dashed ones are 24, 50 and 135mm on full frame from the same spot. Its APS-C sensor (23.5 x 15.6 mm) has a crop factor of 1.5, so the dashed frames are marked with the focal length that gives the same view on it.
18mm on the Leica TL2 frames 6.53 m × 4.33 m at 5 m: like 27mm on full frame, 66° across.
The numbers
- Frame at 5 m6.53 m × 4.33 m
- Full-frame equivalent27mm
- Angle of view66° × 47°, 76° diagonal
- Depth of field at f/2.82.76 m to 26.3 m (23.5 m)
- Depth of field at f/81.51 m to infinity (to infinity)
- Hyperfocal at f/2.86.17 m
- Hyperfocal at f/82.17 m
- Circle of confusion0.019 mm
How it is worked out
The frame at a distance is distance × sensor size ÷ focal length, across and up; the angle of view is 2 × atan(sensor size ÷ (2 × focal length)). Depth of field uses the thin-lens formulas: the hyperfocal distance H = f² ÷ (N × c) + f, the near limit s(H − f) ÷ (H + s − 2f) and the far limit s(H − f) ÷ (H − s), sharp to infinity from H on, with a circle of confusion c of the sensor diagonal ÷ 1500 and, on a zoom whose aperture changes, the maximum aperture taken linearly between its ends. These are for a rectilinear lens; a fisheye takes in more. Ask for this page with Accept: application/json for the numbers alone.