What it frames
The Canon PowerShot V10 with its built-in 6.6mm f/2.8 lens, over an 8.5 m tree and a 1.75 m person, with hills behind. Everything is drawn to scale: the solid frame is what the camera takes in, the dashed ones are 24, 50 and 135mm on full frame from the same spot. Its 1-inch sensor (13.2 x 8.8 mm) has a crop factor of 2.7, so the dashed frames are marked with the focal length that gives the same view on it.
6.6mm on the Canon PowerShot V10 frames 40 m × 26.7 m at 20 m: like 18mm on full frame, 90° across.
The numbers
- Frame at 20 m40 m × 26.7 m
- Full-frame equivalent18mm
- Angle of view90° × 67°, 100° diagonal
- Depth of field at f/2.81.37 m to infinity (to infinity)
- Depth of field at f/850 cm to infinity (to infinity)
- Hyperfocal at f/2.81.48 m
- Hyperfocal at f/852 cm
- Circle of confusion0.011 mm
How it is worked out
The frame at a distance is distance × sensor size ÷ focal length, across and up; the angle of view is 2 × atan(sensor size ÷ (2 × focal length)). Depth of field uses the thin-lens formulas: the hyperfocal distance H = f² ÷ (N × c) + f, the near limit s(H − f) ÷ (H + s − 2f) and the far limit s(H − f) ÷ (H − s), sharp to infinity from H on, with a circle of confusion c of the sensor diagonal ÷ 1500 and, on a zoom whose aperture changes, the maximum aperture taken linearly between its ends. These are for a rectilinear lens; a fisheye takes in more. Ask for this page with Accept: application/json for the numbers alone.